¿Cómo calcular nuestra frecuencia cardíaca máxima? Existe una fórmula "casera" para calcular nuestra frecuencia cardíaca máxima, aunque se trata de una ecuación con limitaciones porque se creó en base a sujetos de menos de 55 años. Pero, sabiendo esto, puede resultar interesante como orientación o guía. Para calcularla tan solo hay que restar la edad del sujeto a 220 ( FCmáx = 220 – la edad del sujeto). La frecuencias cardiaca máxima por edades se encuentra en torno a los siguientes valores en personas adultas: 20 años: 200 latidos por minuto. 30 años: 190 latidos por minuto. 40 años: 180 latidos por minuto. 50 años: 170 latidos por minuto. 60 años: 160 latidos por minuto. 70 años: 150 latidos por minuto. La frecuencia cardiaca basal sería el extremo opuesto a la máxima, la mínima frecuencia que podemos mantener para que nuestras constantes vitales sigan activas (que no es la mismo que la de reposo). Aunque podamos medir estos valores en casa, es interesante que sea un especialista quien valore, sobre todo, la frecuencia cardíaca máxima, con una prueba de esfuerzo, en caso de que la persona necesite conocerla por su desempeño deportivo.
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(i) Ones are subtracted, 0 < 2, so 1 ten is borrowed from tens. Now 1 Ten or 10 + 0 = 10, 10 – 2 = 8
(ii) Tens are subtracted, 3Tens – 3Tens = 0
(iii)Hundreds are subtracted, 3 Hundreds < 7 Hundreds so, 1 Thousand is borrowed, so 10 Hundreds + 3 Hundreds = 13 Hundreds,
13 Hundreds – 7 Hundreds = 6 Hundreds. (iv) Thousands are subtracted, 8Thousands – 6Thousands = 2Thousands
Hence, difference = 2, 608 3. What is the difference between 40712 and 7549? (with borrowing)
(i) 2 < 9, 1T or 10 is borrowed 10 + 2 = 12,
12 – 9 = 3
(ii) 0 < 4, 1H or 10T is borrowed 10T + 0 = 10T, Now 10T – 4T = 6T
(iii) 6H – 5H = 1H
(iv) 1 Tth is borrowed, 10Th – 7Th = 3 Th
(v) 3Tth – 0 = 3Tth
So, difference = 33, 163
4. Subtract 2 3 7 4 1 2 from 6 4 9 5 2 3 (without borrowing)
Numbers are arranged in column form
(i) 3 – 2 = 1 Ones
(ii) 2 – 1 = 1 Tens
(iii) 5 – 4 = 1 Hundreds
(iv) 9 – 7 = 2 Thousands
(v) 4 – 3 = 1 Ten thousands
(vi) 6 – 2 = 4 Hundred thousands
Therefore, difference = 412111
5. Subtract (with borrowing) 6 5 6 2 9 from 3 2 3 4 7 8
(i) Ones: 8 < 9, IT or 10 is borrowed 10 + 8 = 18, 18 - 9 = 9
(ii) Tens: 6T - 2T = 4T
(iii) Hundreds: 4H < 6H, 1 th or 10H is borrowed, 10H + 4H = 14H, 14H - 6H = 8H
(iv) 2Th < 5Th, 1Tth or 10Th is borrowed 10Th + 2Th = 12Th, 12Th - 5Th = 7Th
(v) 1Tth < 6Tth, 1Hth or 10Tth is borrowed 10Tth + 1Tth = 11Tth, 11Tth - 6Tth = 5Tth
(vi) 2Hth remained as it was.
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